Hcf of 625 3125 15625
WebSep 26, 2024 · Now, we have to find the H.C.F. of 625, 3125 and 15625. First we find the HCF of 625 and 3125. By applying Euclid’s division lemma,a = bq+r Let a = 3125 and b = 625 3125 = 625 x 5 + 0. Here remainder is zero , and the last divisor is 625. So H.C.F. of 625 and 3125 is 625. Now,we find the HCF of 625 and 15625. WebIn order to find the largest number which divides 626, 3127 and 15628 leaving remainders 1, 2 and 3. We get. 626 – 1 = 625. 3127 – 2 = 3125. 15628 – 3 = 15625. So the required number = HCF of 625, 3125 and …
Hcf of 625 3125 15625
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WebOct 3, 2024 · To find HCF of 625, 3125 and 15625 first we will find HCF of 625 and 3125 and then we will find HCF of HCF of (625 & 3125) and 15625. Step (1): HCF of 625 and … WebApr 22, 2024 · Therefore HCF of 625, 3125 and 15625 is: 5 × 5 × 5 × 5 = 625 Hence the largest number which divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively is 625 ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET Mock Test Class 12 Chapterwise MCQ Test Class 11 …
WebApr 22, 2024 · 625 = 625 x 1 + 0. 3125 = 625 x 5 + 0. 15625 = 625 x 25 + 0. Hence H.C.F of 625, 3125 and 15625 = 625 Web626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 has to be exactly divisible by the number. Thus, the required number should be the HCF of 625, 3125 and 15625. First, consider 625 and 3125 and apply Euclid’s division lemma. 3125 = …
WebThe decimal part is: .15625 = 15625 / 100000 Full simple fraction breakdown: 15625/100000 = 3125/20000 = 625/4000 = 125/800 = 25/160 = 5/32. Scroll down to customize the precision point enabling 0.15625 to be broken down to a specific number of digits. The page also includes a pie chart representation of 0.15625 in fraction form. WebJan 16, 2024 · Find the HCF of 625,3125,15625 Advertisement Answer No one rated this answer yet — why not be the first? 😎 aarav873 the HCF is 15625 I hope this helps you if the answer is correct please mark me as a brainliest Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1
WebIn order to find the largest number which divides 626, 3127 and 15628 leaving remainders 1, 2 and 3 We get 626 – 1 = 625 3127 – 2 = 3125 15628 – 3 = 15625 So the required number = HCF of 625, 3125 and 15625 By resolving the required number into prime factors we get 625 = 5 × 5 × 5 × 5 3125 = 5 × 5 × 5 × 5 × 5 15625 = 5 × 5 × 5 × 5 × 5 × 5 So the …
WebJan 24, 2024 · Step (1) : HCF of 625 and 3125 by using Uuclid's division algorithm is 3125=625×5+0⇒H CF of 625 and 3125 is 625. Step (2) : Now HCF of 625 and 15625 will 15625=625×25+0 ⇒ HCF of 625 and 15625 is 625 . Hence HCF of 625, 3125 and 15625 is 625. nce required number is 625 . View solution my fed weekWebClearly the required number is the HCF of the following numbers 626 - 1 = 625, 3127 - 2 = 3125 and 15628 - 3 = 15625 Case I. Finding the HCF of 625 and 3125 by applying Euclid’s division lemma. I. 3125 = 625 × 5 + 0 Since, the remainder at this stage is zero, so the divisor i.e., 625 at this stage is the HCF of 625 and 3125. Case II. my fed loan servicerWebThis means 626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 are completely divisible by the number ∴ The required number = HCF of 625, 3125 and 15625 First consider 625 and 3125 By applying Euclid’s division lemma 3125 = 625 × 5 + 0 HCF of 625 and 3125 = 625 Now consider 625 and 15625 By applying Euclid’s division lemma 15625 = 625 × 25 … off the lip hairWebThus, the required number should be the H.C.F of 625, 3125, and 15625. First, consider 625 and 3125 and apply Euclid’s division lemma. 3125 = 625 x 5 + 0. ∴ H.C.F (625, 3125) = 625. Next, consider 625 and the third number 15625 to apply Euclid’s division lemma 15625 = 625 x 25 + 0. We get, the HCF of 625 and 12625 to be 625. my fed retirement werksWebHCF Calculator: Finding the Highest Common Factor is similar to the Greatest common factor or divisor as HCF is also known as GCF or GCD. You can calculate HCF of given numbers easily by approaching the … off the line wineWeb15628 – 3 = 15625 are completely divisible by the number. ∴ The required number = HCF of 625, 3125 and 15625. First consider 625 and 3125. By applying Euclid’s division lemma. … off the list 意味WebFeb 28, 2024 · So, the HCF of 15625 and 625 is 625. Hence HCF of 625, 3125 and 15625 is 625. Note: During solving this question you can use any one of the methods, but the first … my fed rooms